1970-01-01

(2026-01) A SNARK for (Non-)Subsequences with Text-Sub-Linear Proving Time

[[Dario Fiore]]
[[San Ling]]
[[Khai Hanh Tang]]
[[Hong Hanh Tran]]
[[Huaxiong Wang]]
[[Yingfei Yan]]

2026-01-04

Abstract

A keyword $\mathbf{s}$ is a subsequence of a text $\mathbf{t}$ if $\mathbf{s}$ can be obtained by deleting some characters from $\mathbf{t}$ ; otherwise, $\mathbf{s}$ is a non-subsequence of $\mathbf{t}$ . (Non-)subsequence relationships arise in various fields, including genetic analysis, blockchains, and natural language processing. Recently, Ling et al. (SCN 2024) proposed a succinct argument for non-subsequences based on multivariate sumcheck (Lund et al., FOCS 1990) whose prover's running time is at least $\mathcal{O}(n + N + |\Sigma|)$ , where $n$ and $N$ are respectively the lengths of strings $\mathbf{s}$ and $\mathbf{t}$ , and $\Sigma$ is the alphabet over which $\mathbf{s}$ and $\mathbf{t}$ are defined. As shown in their work, proving non-subsequence relationships is non-trivial since one needs to decompose such an argument into smaller components for sumcheck, permutation, and lookup.

We propose a subsequence scheme that separates proving (non-)subsequences into the following two phases: (i) a preprocessing phase and (ii) a (non-)subsequence proving phase, assuming $n \ll N$ (i.e., $|\mathbf{s}| \ll |\mathbf{t}|$ ). Specifically, we can generate a one-time preprocessing proof with inputs $\mathbf{t}$ and $\Sigma$ , without any knowledge of $\mathbf{s}$ . When $\mathbf{s}$ is known, we can determine whether $\mathbf{s}$ is a subsequence of $\mathbf{t}$ and prove the corresponding statement. Employing cached quotients (IACR ePrint 2022/1763), we achieve a running time quasi-linear in $N + |\Sigma|$ for preprocessing, while the running time of proving a (non-)subsequence relationship is $\mathcal{O}(n \log_2 (N + |\Sigma|))$ for each query $\mathbf{s}$ . Since $n \ll N$ and $\log_2(N + |\Sigma|)$ grows sub-linearly with the text size, this saves the prover's running time, assuming a preprocessing depending only on $\mathbf{t}$ is computed in advance. Hence, we achieve a \textit{text-sub-linear} proving time.